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5x^2+22x+16=x
We move all terms to the left:
5x^2+22x+16-(x)=0
We add all the numbers together, and all the variables
5x^2+21x+16=0
a = 5; b = 21; c = +16;
Δ = b2-4ac
Δ = 212-4·5·16
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-11}{2*5}=\frac{-32}{10} =-3+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+11}{2*5}=\frac{-10}{10} =-1 $
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